In this case of genotype AABbCc, A gene will give only one type of gamete, B can give two types of gametes and c can give two types of gametes. Thus, totally four types of gametes will be produced.
How many gametes would be formed from a genotype AABbCC?
Complete answer: AABbcc will produce 2 types of gametes which are as follows- ABc, Abc. The number of gametes formed is set by the number of heterozygous alleles present within the given genotype.
How many types of gametes would be produced if the genotype of a parent is AABbCC A 4 B 6 C 8 D 16?
So, the correct answer is ‘Four’.
How many types of gametes are found in f1 progeny of cross AaBbCc and AaBbCc?
Therefore, types of gametes possible is 23=8.
What skin color is AaBbCc?
Each dark skin allele (A,B,C) in the genotype adds a small but equal amount of pigment to the skin. There are seven different shades of skin color ranging from very dark (AABBCC) to very light (aabbcc). Most individuals produce a medium amount of melanin and are of intermediate skin color (AaBbCc).
How many gametes does Trihybrid produce?
The F1 hybrid produces 8 types of gametes.
How many types of gametes will be produced from the genotype AaBb?
Possible gametes for each AaBb parent
Since each parent has four different combinations of alleles in the gametes, there are sixteen possible combinations for this cross.
How many types of gametes can be produced?
The number of different possible gametes produced by the diploid genotype (AaBbCcDdEe) is 2 x 2 x 2 x 2 x 2 = 32 (2 for each pair of heterozygous genes).
How many types of gametes can be formed in F1 progeny?
8 gametes will be formed by F1 progeny, from the following cross.
How many types of gametes are formed from a F1 plant?
Two types of gametes will be produced in the F2 generation of a monohybrid cross of Mendel. Pure line (homozygous e.g. TT/tt) parents will produce hybrids (heterozygotes e.g. Tt) in the F1 generation. In the F2 generation, these hybrids will produce only two types of gametes (e.g. T and t).
How many different types of gametes can be formed by the F1 progeny resulting from the following cross?
|Question||How many different types of gametes can be formed by F1 progeny resulting from the following cross? AABBCC × aabbcc|
|Type of Answer||Video, Text & Image|
What will be the probability of obtaining a plant with AAbbcc genotype from Trihybrid AAbbcc parents?
So, the correct answer is ‘1/8. ‘ Note: Traditional method of solving this problem can be by using the punnett square. So, if we look into the punnett square of a normal trihybrid cross, we can get the probability by looking into the genotype.
How many types of phenotype and genotype will be formed in f2 generation explain the example with the help of checker board?
The phenotypic and genotypic ratio in f2 generation is 1:2:1 (red RR : roan Rr : white rr) – Totally three different genotypes/phenotypes. It is important to note that in co-dominance, the phenotypic and genotypic ratio are the same.
How many pairs of genes control skin color?
Note: Skin color may involve at least four pairs of alleles with nine (or more) shades of skin color.