# Quick Answer: What is the probability of getting an ABC gamete from a parent who is AaBbCc?

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This is a percentage of 3.1%.

## How many possible gametes are there if the parent is AaBbCc?

Hints For Biology 101 Exam #4

No. of homologous chromosome pairs (heterozygous genes) No. of different gametes from each parent
1 (Aa X Aa) 2 (21)
2 (AaBb X AaBb) 4 (22)
3 (AaBbCc X AaBbCc) 8 (23)
4 (AaBbCcDd X AaBbCcDd) 16 (24)

## How many types of gametes are produced by AaBbCc and AaBbCc?

So, the correct answer is ‘Four’.

## What is the probability of getting the gamete AB from the parent AaBb?

AaBB, the probability of generating an AB gamete is 1/2. For genotype AABb, the probability of generating an AB gamete is 1/2. Again, because both genotypes have equal probabilities, the final probability of the parent generating an AB gamete is (1/2) × (1/2) + (1/2) × (1/2) = 2/4 = 0.5 = 50%.

## What is the probability that parents AaBb and AaBb will have offspring with genotype AaBb?

The correct answer: The probability of an aabb offspring when AaBb x AaBb parents are crossed is b. 1/16 .

## How many types of gametes are formed by a plant having AABbCC genotype in which A & B genes shows complete linkage?

In this case of genotype AABbCc, A gene will give only one type of gamete, B can give two types of gametes and c can give two types of gametes. Thus, totally four types of gametes will be produced.

## How many types of gametes will be formed by AaBb genotype?

There are four possible combinations of gametes for the AaBb parent. Half of the gametes get a dominant A and a dominant B allele; the other half of the gametes get a recessive a and a recessive b allele. Both parents produce 25% each of AB, Ab, aB, and ab.

## What is the probability of an offspring being homozygous?

If two homozygous dominants are crossed, the probability that an offspring will be homozygous dominant is 100% or 1.00. 8. If two homozygous recessives are crossed, the probability that an offspring will be homozygous recessive is 100% or 1.00.

## What is the probability that a child of two a Parents will be albino?

The chance that each child will have two broken copies of the gene (rr) and have albinism is 1 in 4. This is what happened in your wife’s aunts and uncle. The chance that each child will have at least one working copy of the gene (RR or Rr) and not have albinism is 3 in 4.

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## What is the probability that the first child will have curly hair?

The probability of curly hair for the first child is 50 percent, since the straight gene is dominant and present on the X chromosome.

## When two hybrids AaBb and AaBb are crossed the phenotypic ratio of offspring will be?

(a) Two pea plants with green pods, Gg×GG, were crossed. Complete the given Punnett square to show the results of this cross. (b) What percentage of the offspring produced by this cross will most likely have green pods?

## What would be the phenotypic ratio produced by a cross between AaBb and AaBb?

A Punnet Square for the AaBb x AaBb cross is shown below. Rather than the 9:3:3:1 seqregation of phenotypes normally seen with an AaBb x AaBb dihybrid cross, the phenotypic ratio is 9:3:4.

## How many types of gametes would be produced if the genotype of a parent is AaBb A 1 B 2 C 3 D 4?

If the genotype of a parent is AaBB then 2 types of gametes will be produced.