What is p2 in the Hardy Weinberg equation?

What does p2 represent in the Hardy Weinberg formula?

In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.

How do you find P 2 in Hardy Weinberg?

Since p = 1 – q then 1 – 0.59 = 0.41. Now that we know the frequency of each allele, we can calculate the frequency of the remaining genotypes in the population (AA and Aa individuals). AA = p2 = 0.41 x 0.41 = 0.17; Aa = 2pq = 2 (0.59) (0.41) = 0.48; and as before aa = q2 = 0.59 x 0.59 = 0.35.

What does P represent in Hardy Weinberg?

In order to express Hardy Weinberg principle mathematically , suppose “p” represents the frequency of the dominant allele in gene pool and “q” represents the frequency of recessive allele.

How do you calculate P and Q?

We can calculate the values of p and q, in a representative sample of individuals from a population, by simply counting the alleles and dividing by the total number of alleles examined. For a given allele, homozygotes will count for twice as much as heterozygotes.

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Why is 2pq not PQ?

Note that the heterozygotes are not 2pq but pq because in each case they are only being considered for the one allele in question. If we scale all wii’s such that the largest = 1.0 we refer to these as the relative fitnesses of the genotypes. A worked example where p = . 4, q = .

Why is there a 2 in 2pq but not in p2 nor q2?

9. Why is there a “2” in “2pq” but not in “p2” nor “q2”? 16% of a population is unable to taste the chemical PTC. These non- tasters are recessive for the tasting gene.

Is PP genotype or phenotype?

There are three available genotypes, PP (homozygous dominant ), Pp (heterozygous), and pp (homozygous recessive). All three have different genotypes but the first two have the same phenotype (purple) as distinct from the third (white).

How do you find the frequency of P?

Once we know q, we can simply subtract q from 1 to find the frequency of p. This works only in a simplified scenario, where p and q are the only alleles and account for 100% of the total alleles. In this case, p will be equal to 60% of the alleles, or 0.6.

How do you find the P and Q values in Hardy-Weinberg?

The Hardy-Weinberg equation used to determine genotype frequencies is: p2 + 2pq + q2 = 1. Where ‘p2‘ represents the frequency of the homozygous dominant genotype (AA), ‘2pq’ the frequency of the heterozygous genotype (Aa) and ‘q2‘ the frequency of the homozygous recessive genotype (aa).

Where is 2pq from?

Explanation: In the Hardy-Weinberg equilibrium equation ( p2+2pq+q2=1 ), the term 2pq represents the genotype frequency of heterozygotes (Aa) in a population in equilibrium. The term p2 represents the frequency of dominant homozygotes (AA) and the term q2 represents the frequency of recessive homozygotes (aa).

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How do you calculate W Bar?

Take the Hardy-Weinberg equation and multiply each term (the frequency of each genotype) by the fitness of that genotype. Add those up and you get the mean fitness, w (“w-bar”).

How do you find the genotype and allele frequency?

To find the allele frequencies, we again look at each individual’s genotype, count the number of copies of each allele, and divide by the total number of gene copies.